Tests: Compare the length of cluster states serialized as a String, not the binary representation.

Due to the fact that the binary representation uses some compression, we can't
be sure that they will be equal even if they store the same content.

src/test/java/org/elasticsearch/test/ElasticsearchIntegrationTest.java

@@ -1170,7 +1170,7 @@ public abstract class ElasticsearchIntegrationTest extends ElasticsearchTestCase
                 // remove local node reference
                 masterClusterState = ClusterState.Builder.fromBytes(masterClusterStateBytes, null);
                 Map<String, Object> masterStateMap = convertToMap(masterClusterState);
-                int masterClusterStateSize = ClusterState.Builder.toBytes(masterClusterState).length;
+                int masterClusterStateSize = masterClusterState.toString().length();
                 String masterId = masterClusterState.nodes().masterNodeId();
                 for (Client client : cluster()) {
                     ClusterState localClusterState = client.admin().cluster().prepareState().all().setLocal(true).get().getState();
@@ -1178,7 +1178,7 @@ public abstract class ElasticsearchIntegrationTest extends ElasticsearchTestCase
                     // remove local node reference
                     localClusterState = ClusterState.Builder.fromBytes(localClusterStateBytes, null);
                     Map<String, Object> localStateMap = convertToMap(localClusterState);
-                    int localClusterStateSize = localClusterStateBytes.length;
+                    int localClusterStateSize = localClusterState.toString().length();
                     // Check that the non-master node has the same version of the cluster state as the master and that this node didn't disconnect from the master
                     if (masterClusterState.version() == localClusterState.version() && localClusterState.nodes().nodes().containsKey(masterId)) {
                         try {